How will you explain buffer action of aqueous solution of ammoni

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 Multiple Choice QuestionsShort Answer Type

291.

Calculate the degree of hydrolysis of 0.015 M solution of NH4Cl. Given Kb for NH4OH is 1·8 × 10–5, Kw = 10–14at 25°C.

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 Multiple Choice QuestionsLong Answer Type

292.

Explain the terms: buffer solution and buffer capacity.

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293.

Show with an example how buffer solution resists the action of acid or base towards change in pH.
Or
Discuss the buffer action of:
(i) acidic buffer
(ii) basic buffer.

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294. How will you explain buffer action of aqueous solution of ammonium acetate?


Ammonium acetate on dissolution dissociates completely as ions.



(i) If an acid (say HCl) is added to this solution, H3O+ ions generated by the acid combine with CH3COO ion to form weakly ionised acetic acid molecules



Since most of H3O+ ions are consumed by CH3COO ions to form slightly dissociated acetic acid, hence the pH value of the solution does not undergo any change.

Now suppose a base (say NaOH) is added to ammonium acetate solution. The OH ions liberated by the base will be consumed by ions to form very slightly dissociated NH4OH. 




Since most of the OH ions are consumed by the  ions, hence there is very little or no change in the pH value of ammonium acetate.
Thus, CH3COONH4 has reserve acidity due to  ions and reserve alkalinity due to CH3COO ions.
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295.

Calculate the pH of:
(i) an acidic buffer mixture 
(ii) a basic buffer mixture.
Or
Derive Henderson’s equation for an acidic and basic buffer mixture.
Or
Derive the following equation for the pH of an acidic buffer:
pH space equals space pK subscript straight a space plus space log space fraction numerator open vertical bar Salt close vertical bar over denominator open vertical bar Acid close vertical bar end fraction

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 Multiple Choice QuestionsShort Answer Type

296. Calculate the pH value of a solution obtained by mixing 0·083 moles of acetic acid and 0·091 moles of sodium acetate and making the volume 500 ml. Ka for acetic acid is 1·75 × 10–5.
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 Multiple Choice QuestionsLong Answer Type

297. Calculate the pH of a solution obtained by mixing 6·0g of acetic acid and 12·30g of sodium acetate and making the volume of solution to 500 ml. Ka for acetic acid is 1·8 × 10–5
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298. Determine the pH of a solution obtained by mixing equal volumes of 0·015N NH4OH and 0·15N NH4NO3 solutions. (Kb for NH4OH is 1·8 × 10–5).
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299.

Describe Ostwald’s theory of acid-base indicators.
Or
How does Ostwald’s theory explain the colour change of:
(i) Phenolphthalein
(ii) Methyl orange in acid-base titrations?

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 Multiple Choice QuestionsShort Answer Type

300.

How does the concept of solubility product help in finding out the solubility of sparingly soluble salts?

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