For the following equilibrium, N2O4 2NO2 in the gaseous phase, NO2 is 50% of the total volume when equilibrium is set up. Hence, per cent of dissociation of N2O4 is
50%
25%
66.66%
33.33%
At equilibrium, if KP = 1, then
> 1
< 1
= 0
= 1
C.
= 0
At equilibrium, the relation between free energy of the reaction and equilibrium constant is as follows-
= -RT ln Kp
If Kp = 1 at equilibrium
= -RT ln 1
or, = 0
1 mL of 0.01 N HCl is added to 999 mL solution of 0.1 N Na2SO4. The pH of the resulting solution will
2
7
5
1
The equilibrium constants for the reaction,
Br2 2Br → 1
at 500 K and 700 K are 1 × 10-10 and 1 × 10-5 respectively. The reaction is
endothermic
exothermic
fast
slow
A chemist wishes to prepare a buffer solution of pH = 2.90 that efficiently resists a change in pH yet contains only small concentration of buffering agents which one of the following weak acid along with its salt would be best to use
m-chlorobenzoic acid (pKa = 3.98)
Acetoacetic acid (pKa = 3.58)
2 5-dihydrobenzoic acid (pKa = 2.97)
p-chlorocmanic acid (pKa = 4.41)
NaOH is a strong base. What will the be pH of 5.0 × 10-2 M NaOH solution? (log 2 = 0.3)
14.00
13.70
13.00
12.70
The equilibrium constants of the reactions
and are K1 respectively. The relationship between K1 and K2 will be
K2
K2 = √K1
K1= K2
The value of Kc for the dissociation reaction, H2 (g) 2H (g) is 1.2 × 10-42
This equilibrium mixture contains mainly
H2 (g)
H (g) atom
1.1 M mixture of H2 and H
1.2 M mixture of H2 and H