73.
Explain the formation of two products in the following reactions:
CH3CH = CHCH2Cl + H2O →
CH3CH = CH.CH2OH + CH3CH(OH)CH = CH
In this reaction two products are formed. It is because when the alkenes are unsymmetrical then two products are formed. In the above reaction the compound 1-chloro-2-butene is an unsymmetrical. Therefore on hydrolysis it forms two products.
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