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 Multiple Choice QuestionsShort Answer Type

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231.

A hydrocarbon C5H10 does not react with chlorine in dark but gives a single monochloro compound C5H9Cl in bright sunlight. Identify the hydrocarbon.


The hydrocarbon can be either a cycloalkane or an alkene since it does n’t react with Cl2 in the dark, it can not be an alkene but must be cycloalkane since the cycloalkane reacts with Cl2 in the presence of sunlight to give a single monochloro derivative. It shows that it is cyclic hydrocarbon in which hall the hydrogen atoms are identical. Thus, it can be only cyclopentane. 

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232.

Write the isomers of the compound having formula C4H9Br.

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 Multiple Choice QuestionsLong Answer Type

233.

Write the structures of isomers of C5H11Br.

 
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 Multiple Choice QuestionsShort Answer Type

234. Amongst the aromatic compounds having molecular formula C7H7Cl, how many isomers are possible?
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235.

Write the equations for the preparation of 1-iodobutane from 1-Butanol

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236.

Write the equations for the preparation of 1-iodobutane from 1-chlorobutane.

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237.

Write the equations for the preparation of 1-iodobutane from but-1-ene. 

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238.

How will you bring about the following conversions?
 Ethanol to But-1-yne.

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239.

How will you bring about the following conversions?
ii) Ethane to Bromoethene

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240.

How will you bring about the following conversions?
 Propene to 1-nitropropane

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