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 Multiple Choice QuestionsMultiple Choice Questions

491.

The product (Z) of the following reaction is:

       


492.

What is the product in the following reaction?

  • Benzoquionone

  • Cyclohexane-1-one

  • Benzoic sulphate

  • Benzoric acid


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493.

Which one of the following has highest boiling point?

  • H3CCH2CH2CH2Cl

  • (H3C)2CHCH2Cl

  • (H3C)3CCl

  • H3CCH2CHClCH3


A.

H3CCH2CH2CH2Cl

(H3C)2CHCH2Cl

For isomeric alkyl halides, the boiling points decreases with branching. Branching of the chain makes the molecule more compact and therefore, the surface area decreases. Hence, the intermolecular attractive forces which depend upon the surface area, also become small In magnitude due to branching. Consequently, the boiling points of the branched chain having same molecular formula are less than the straight chain isomers. Higher the molecular weight, higher is the boiling point, but branching reduces boiling point.


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494.

The product Z of the following reaction is H3CC≡CH 2HBr Z.

  • H3CCH2CHBr2

  • H3CCBr2CH3

  • H3CCHBrCH2Br

  • BrCH2CH2CH2Br


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495.

Identify X and Y in the following reaction sequence

X Zn Y Zn-H2OO3 (CH3)2CO + CH2O

  •  

    X Y
    (CH3)2CHBrCH3 CH3CH=CHCH3
  • X Y
    (CH3)2CHCH2Br CH3CH=CHCH3
  • X Y
    (CH3)2CBrCH2Br (CH3)2C=CH2
  • X Y
    (CH3)2CHCHBr2 (CH3)2C=CH2

496.

Oxidation of cyclohexene in presence of acidic potassium permaganate leads to

  • glutaric acid

  • adipic acid

  • pimelic acid

  • succinic acid


497.

Cyclopentadienyl anion is

  • benzenoid and aromatic

  • non-benzenoid and aromatic

  • non-benzenoid and non-aromatic

  • non-benzenoid and anti- aromatic


498.

The reactivity of alkyl bromides.

 

Towards iodide ion in dry acetone decrease in the order

  • V > I > II > III

  • I > IV> II> III

  • III> II> I> I

  • III > II > IV > I


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499.

Optically active CH3—CH2—CHOH—CH3 was found to have lost its optical activity after standing in water containing a few drops of acids, mainly due to the formation of 

  • CH3—CH2—CH=CH2

  • CH3—CH=CH—CH3

  • CH3—CH(CH3)—CH2—OH

  • CH3—CH2—CH2—CH2—OH


500.

Which one of the following alkenes when treated with HCl yields majority an anti Maxkovnikov product?

  • CH3O-CH=CH2

  • Cl-CH=CH2

  • F3C-CH=CH2

  • H2N-CH=CH2


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