Friedel-Craft's reaction using MeCl and anhydrous AlCl3 will take place most efficiently with:
benzene
nitrobenzene
acetophenone
toluene
The ease of nitration of the following three hydrocarbons follows the order:
II = III = I
II > III > I
III > II > I
I = III > II
B.
II > III > I
The ease of nitration of the hydrocarbons depends upon the stability of arenium ion formed.
In compound II, the carbonium ion has two methyl groups (with +I effect) capable of partially neutralising the positive charges on the ring carbon atoms. In compound I and II, only one methyl group can act in this way. Moreover, in compound III two methyl groups have +I effet, whereas in compound I only one methyl group with +I effect is present. Thus, the stability of arelium ion and ease of nitration follows the order,
II > III > I
Among the alkenes which one produces tertiary butyl alcohol on acid hydration?
CH3-CH2-CH=CH2
CH3-CH=CH-CH3
(CH3)2C=CH2
CH3-CH=CH2
Nitrobenzene on reaction with conc. HNO3/H2SO4 at 80-100°C forms which one of the following products?
1, 2-dinitrobenzene
1, 3-dinitrobenzene
1, 4-dinitrobenzene
1, 2, 4-trinitrobenzene
Some meta-directing substituents in aromatic substitution are given. Which one is most deactivating?
The radical because it has
6p-orbitals and 6 unpaired electrons
7p-orbitals and 6 unpaired electrons
7p-orbitals and 7 unpaired electrons
6p-orbitals and 7 unpaired electrons
Which of the following compounds will not undergo Friedal-Craft's reaction easily?
Cumene
Xylene
Nitrobenzene
Toluene