The compound that can work both as an oxidising as well as reducing agent is
KMnO2
H2O2
Fe2(SO4)3
K2Cr2O7
B.
H2O2
The oxidation number of O in H2O2 is -1. It can either increases to zero in O2 or decreases to -2 in H2O. Therefore, H2O2 can act both as an oxidising as well as a reducing agent.
Which one of the following is not a method to remove permanent hardness of water?
Clark's method
Calgon method
Ion- exchange method
Synthetic resins methods
Reaction of calgon with hard water containing Ca2+ ions produce
[Na2CaP6O18]2-
CaCO3
CaSO4
Ca2(PO4)3
Diborane (B2H6) reacts independently with O2 and H2O to produce, respectively:
B2O3 and H3BO3
H3BO3 and B2O3
B2O3 and [BH4]-
HBO2 and H3BO3
100 mL of a water sample contains 0.81 g of calcium bicarbonate and 0.73 g of magnesium bicarbonate. The hardness of this water sample expressed in terms of equivalents of CaCO3 is: (molar mass of calcium bicarbonate is 162 g mol-1 and magnesium bicarbonate is 146 g mol-1)
1,000 ppm
100 ppm
10,000 ppm
5000 ppm
Which of the following statement about hydrogen is incorrect?
Hydrogen never acts as cation in ionic salts
Hydronium ion, H3O+ exist freely in solution
Dihydrogen does not act as a reducing agent
Dihydrogen does not act as a reducing agent
The reaction of aqueous KMnO4 with H2O2 in acidic conditions gives.
Mn4+ and O2
Mn2+ and O2
Mn2+ and O3
Mn2+ and O3
A hydrogen gas electrode is made by dipping platinum wire in a solution of HCl of pH =10 and by passing hydrogen gas through the platinum wire at 1 atm pressure. The oxidation potential of electrode would be
0.0591 V
0.59 V
0.118 V
0.118 V