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101.
Determine the oxidation number of C in the following:

$bold left parenthesis bold i bold right parenthesis bold space bold C subscript bold 2 bold H subscript bold 6 bold space bold space bold space bold space bold space bold space bold space bold space bold space bold left parenthesis bold ii bold right parenthesis bold space bold C subscript bold 4 bold H subscript bold 10 bold space bold space bold space bold space bold space bold space bold space bold space bold space bold left parenthesis bold iii bold right parenthesis bold space bold CO bold left parenthesis bold iv bold right parenthesis bold space bold CO subscript bold 2 bold space bold space bold space bold space bold space bold space bold space bold space space space$

C₂H₆: Let the oxidation number of C= x
Oxidation number of H = 1
The algebraic sum of the oxidation number of various atoms = 0

(ii) C₄H₁₀:
Let the oxidation number of C = x
Writing the oxidation number of each atom at the top of its symbol,
x +1
C₄ H₁₀
The algebraic sum of the oxidation number of various atoms = 0

4x + 10(+1) = 0
or 4x = -10

or

(iii) CO:
Let the oxidation number of C = x
Writing the oxidation number of each atom at the top of its symbol,
x -2
C O
The algebraic sum of the oxidation number of various atoms = 0

x - 2 = 0
or x = 2

(iv) CO₂:
Let the oxidation number of C = x
Writing the oxidation number of each atom at the top of its symbol,
x -2
C O₂

The algebraic sum of the oxidation number of various atoms = 0