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Redox Reactions

Long Answer Type

121.

Write the various steps for balancing a redox equation by oxidation number method.

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Short Answer Type

122. Can you store copper sulphate solutions in a zinc pot?

Zinc is more reactive than copper. Therefore, zinc can displace copper from its salt solution. If copper sulphate solution is stored in a zinc pot, then zinc will displace copper from the copper sulphate solution.
CuSO₄ +Zn → ZnSO₄ +Cu

Hence, copper sulphate solution cannot be stored in a zinc pot

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123.

Balance the following equation by oxidation number method.

$bold space bold space bold FeCl subscript bold 3 bold space bold plus bold space bold H subscript bold 2 bold S bold space bold space bold rightwards arrow bold space bold space bold space bold FeCl subscript bold 2 bold space bold plus bold space bold HCl bold space bold plus bold space bold S$

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124.

Balance the following equation by oxidation number method:
$straight P space plus space HNO subscript 3 space space rightwards arrow space space space HPO subscript 3 space plus space NO space plus space straight H subscript 2 straight O$

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125.

Balance the following equation by oxidation number method:

$SnO subscript 2 space plus space straight C space rightwards arrow space space space Sn space plus space CO$

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126. Balance the equation by oxidation number method:

bold space bold Fe subscript bold 2 bold O subscript bold 3 bold space bold plus bold space bold C bold space bold space bold rightwards arrow bold space bold space bold space bold space bold Fe bold space bold plus bold space bold CO

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Long Answer Type

127. Balance the euqation by oxidation number method:

straight C subscript 6 straight H subscript 6 space plus space straight O subscript 2 space space space rightwards arrow space space space CO subscript 2 space plus space space straight H subscript 2 straight O

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128. Balance the following,chemical equation by oxidation number method:

FeS subscript 2 space plus space straight O subscript 2 space space rightwards arrow space space space Fe subscript 2 straight O subscript 3 space plus space SO subscript 2

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129. Balance the following,chemical equation by oxidation number method:

Mn to the power of 2 plus end exponent space plus space straight S subscript 2 straight O subscript 8 superscript 2 minus end superscript space space space space rightwards arrow space space space space stack MnO subscript 4 superscript minus space plus space HSO subscript 4 superscript minus with left parenthesis acidic space medium right parenthesis below

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130.

Balance the following chemical equation by oxidation number method:
$Zn space plus space NO subscript 3 superscript minus space space rightwards arrow space space space Zn to the power of 2 plus end exponent space plus space left parenthesis NH subscript 4 right parenthesis to the power of plus$ in acidic medium.

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