Write the various steps for balancing redox equation by ion-elec

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 Multiple Choice QuestionsLong Answer Type

131.

Balance the following equation by oxidation number method:
Fe to the power of 2 plus end exponent space plus space Cr subscript 2 straight O subscript 7 superscript 2 minus end superscript space plus space straight H to the power of plus space space rightwards arrow space space Fe to the power of 3 plus end exponent space plus space 2 Cr to the power of 3 plus end exponent space plus space 3 straight H subscript 2 straight O

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132.

Balance the following equation by oxidation number method:
left enclose CrO subscript 4 right parenthesis to the power of 2 minus end exponent space plus space space left parenthesis SO subscript 3 right parenthesis to the power of 2 minus end exponent space space space rightwards arrow space space end enclose open vertical bar Cr left parenthesis OH right parenthesis subscript 4 close vertical bar to the power of 1 minus end exponent space plus space left parenthesis SO subscript 4 right parenthesis to the power of 2 minus end exponent
(in alkaline medium)




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133.

Balance the following redox reaction by oxidation number method:

   left parenthesis Cr left parenthesis OH right parenthesis subscript 4 superscript minus space plus space straight H subscript 2 straight O subscript 2 space space rightwards arrow space space space space CrO subscript 4 superscript 2 minus end superscript space plus space straight H subscript 2 straight O space
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space left parenthesis Basic space medium right parenthesis

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134.

Balance the following equation:
Cr left parenthesis OH right parenthesis subscript 3 space plus space IO subscript 3 superscript minus space space space rightwards arrow space space space CrO subscript 4 superscript 2 minus end superscript space plus space straight I to the power of minus
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space left parenthesis basic space medium right parenthesis space space space space space space space space


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135. Write the net ionic equation for the reaction of potassium dichromate (VI), K2Cr2O7 with sodium sulphite, Na2SO3, in an acid solution to give chromium (III) ion and the sulphate ion.
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136.

With the net ionic equation for the reaction of potassium dichromate (VI), K2Cr2O7 with sodium sulphite, Na2SO3, in an acid solution to give chromium (III) ion and the sulphate ion.

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137. Write the various steps for balancing redox equation by ion-electron method (Half reaction method).


Balancing of equation of ion-electron method involves the following steps:

1. Identify oxidation and reduction half reactions in noting the change in oxidation number of atoms of different species in the reaction and write them separately.

2. Balance the atoms of all elements other than hydrogen and oxygen in both oxidation and reduction half reactions separately.

3. Now add required number of electrons (towards R.H.S. in oxidation half reaction and towards L.H.S. in reduction half reaction) in order to balance the charges of the atom undergoing oxidation or reduction on both the sides of the half reactions.

4. For a reaction taking place in an acidic or neutral medium, balance oxygen atoms by adding an H2O molecule for each oxygen atom on the side deficient in oxygen atoms in each half reaction and now balance hydrogen atom by adding H+ ion for each H atom on the side deficient in hydrogen.

5. If the reaction is carried in a basic solution, change each H+ ion to a water molecule and add an equal number of OH- ions to the opposite side of the equation.

6. Add the two balanced half equations and cancel any term common to both the sides.

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138.

Balance the equation by half reaction method:

straight I subscript 2 space plus space OH to the power of minus space space space space space rightwards arrow space space space space IO subscript 3 superscript minus space plus space straight I to the power of minus space plus space straight H subscript 2 straight O

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139.

Balance the following equation by half reaction method in acidic medium:
MnO subscript 4 superscript minus space plus space Br to the power of minus space space space rightwards arrow space space space Mn to the power of 2 plus end exponent space plus space Br squared

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140. Balance the following equation by half reaction method:
straight H subscript 2 straight S space plus space HNO subscript 3 space space rightwards arrow space space space NO space plus space straight S space plus space straight H subscript 2 straight O
 
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