Balance the following equation by oxidation number method:
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132.
Balance the following equation by oxidation number method: (in alkaline medium)
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133.
Balance the following redox reaction by oxidation number method:
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134.
Balance the following equation:
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135.Write the net ionic equation for the reaction of potassium dichromate (VI), K2Cr2O7 with sodium sulphite, Na2SO3, in an acid solution to give chromium (III) ion and the sulphate ion.
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136.
With the net ionic equation for the reaction of potassium dichromate (VI), K2Cr2O7 with sodium sulphite, Na2SO3, in an acid solution to give chromium (III) ion and the sulphate ion.
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137.Write the various steps for balancing redox equation by ion-electron method (Half reaction method).
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138.
Balance the equation by half reaction method:
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139.
Balance the following equation by half reaction method in acidic medium:
140.Balance the following equation by half reaction method:
(1) Write the oxidation and reduction half-reactions by observing the changes in oxidation numbers and write these separately. -2 0 Oxidation half-reaction: H2S S
+5 +2 Reduction half-reaction: HNO3 NO
(2) To balance the oxidation half reaction. (i) Balancing of S is not required as the number of each S is one on both the sides. 2- 0 H2S S (ii) Add two electrons towards R.H.S. to balance the charges on sulphur atom. 2- 0 (iii) Balance H atoms by adding two H+ towards R.H.S. 2- 0 + (Balanced oxidation half reduction)
(3) To balance the reduction half reaction (i) Balancing of N is not required as the number of each N is one on both the sides. + 5 +2 HNO3 NO (ii) Add 3 electrons towards L.H.S. in order to balance the charges on the nitrogen atom. +5 +2 HNO3 + 3e- NO (iii) Balance the O atoms by adding two H2O molecules on R.H.S. +2 HNO3 + 3e- NO + 2H2O (iv) Balancing H atoms by adding 3H+ on L.H.S. (Balancing reduction half reaction)
4. Multiplying oxidation half-reaction by 3 and reductive half-reaction by 2 to equate the electrons and adding both the half reactions.
Long Answer Type
S
NO
S
+ 
NO
NO
NO + 2H2O
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