During the decomposition of H2O2 to give oxygen, 48 g O2 is forme

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 Multiple Choice QuestionsMultiple Choice Questions

281.

In [NiCl4]2-, the number of unpaired electrons, are

  • 4

  • 2

  • 3

  • 5


282.

H2C2O4 + KMnO4 in acidic medium reacts to have change in oxidation number of Mn from

  • 7 to 5

  • 2 to 7

  • 5 to 7

  • 7 to 2


283.

Oxidation number Fe in K3 [FeCN)6] is

  • +1

  • +2

  • +3

  • +4


284.

Oxidation number of Cr in K2Cr2O7 is

  • 2

  • 4

  • 6

  • 7


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285.

Which of the following is most powerful oxidising agent?

  • I2

  • Cl2

  • Br2

  • F2


286.

Strongest Bronsted base among the following anions is

  • ClO4-

  • ClO3-

  • ClO2-

  • ClO-


287.

The colourless species is

  • VCl3

  • VOSO4

  • Na3VO4

  • [V(H2O)6]SO4.H2O


288.

For which of the following elements it is difficult to disproportionate in +3 oxidation state ?

  • N

  • As

  • Sb

  • Bi


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289.

Substances that are oxidised and reduced in the following reaction are respectively

N2H4 (l) + 2H2O2 (l) N2 (g) + 4H2O (l)

  • N2H4, H2O

  • N2H4, H2O2

  • N2, H2O2

  • H2O, N2


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290.

During the decomposition of H2O2 to give oxygen, 48 g O2 is formed per minute at a certain point of time. The rate of formation of water at this point is

  • 0.75 mol min-1

  • 1.5 mol min-1

  • 2.25 mol min-1

  • 3.0 mol min-1


D.

3.0 mol min-1

The rate of formation of water will be

2H2O2  2H2O + O2

Rate = -12dH2O2dt = 12dH2Odt = dO2dt

rate of formation of oxygen = 48 g min-14832 mol min-1 = 1.5 mol min-1

 Rate of formation of H2O

12dH2Odt = dO2dt dH2Odt = 2 × dO2dt = 2 × 1.5 = 3 mol min-1


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