147.
Vapour pressure of water at 293 K is 17.535 mm Hg. Calculate the vapour pressure of water at 293 K when 25 g of glucose is dissolved in 450 g of water.
Answer:
Vapour pressure of water
Mass of glucose W
2 = 25 g
mass of water w
1 = 450g
we know that
mass of glucose = 180gmol
-1molar mass of glucose =25/180g mol
-1mass of water = 18 g
molar mass of water M
2 = 450/18 g mol
-1
apply equation we get,
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