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 Multiple Choice QuestionsShort Answer Type

221. A 0.1539 molal aqueous solution of cane sugar (mol. mass = 342 g mol–1) has a freezing point of 271 K while the freezing point of pure water is 273.15 K. What will be the freezing point of an aqueous solution containing 5 g of gluocose (mol. mass = 180 g mol–1) per 100 g of solution?
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222.

An aqueous solution of 2 percent non-volatile solute exerts a pressure of 0.096 atm at the boiling poine of the solvent. What is the molecular mass of the solute ?

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223. The vapour pressure of water is 12.3 kPa at 300 K. Calculate the vapour pressure of a one molal solution of a non-volatile, non-ionic solute in water.
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224. Why is the vapour pressure of a solution of glucose in water lower than that of water?


Answer:

The vapour pressure of a pure solvent decrease .
when a non-volatile solute is added to the solvent 
this is because on adding the solute a fewer number of water molecules are present at the surface which can evaporate as some of the area is occupied by -non- volatile solute molecules thereby decreasing the vapour pressure of the solution of the glucose in wateris lower than pure water.

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225. A 6.90 M solution of KOH in water contains 30% by mass of KOH. Calculate the density of the KOH solution. [Molar mass of KOH = 56 g mol–1]
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226. Give reasons for the following:
When 30 ml of ethyl alcohol and 30 ml of water are mixed, the volume of resulting solution is more than 60 ml.
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227. Give reasons for the following:
Copper is conducting as such while copper sulphate is conducting only in molten state or in aqueous solution.
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228. Urea forms an ideal solution in water. Determine the vapour pressure of an aqueous solution containing 10% by mass of urea at 400C. (Vapour pressure of water at 400C = 55.3 mm of Hg)
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229. Why is freezing point depression of 0.1 M sodium chloride solution nearly twice that of 0.1 M glucose solution?
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230. A 6.90 M solution of KOH in water contains 30% by mass of KOH. Calculate the density of the KOH solution. (Molar mass of KOH = 56 g mol–1
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