What is meant by positive deviations from Raoult's law? Give a

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 Multiple Choice QuestionsLong Answer Type

241. Explain with a suitable diagram and appropriate examples. Why some non-ideal solutions show positive deviation from ideal behavior?
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242. Derive an expression relating the elevation of boiling point to the amount of solute present in the solution.
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243. Derive an expression relating the depression of freezing point with the amount of solute present in the solution.
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244. State and explain Raoult’s law. How would you distinguish between an ideal and non-ideal solution?
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 Multiple Choice QuestionsShort Answer Type

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245.

 What is meant by positive deviations from Raoult's law? Give an example. What is the sign of mixH for positive deviation?

OR

Define azeotropes. What type of azeotrope is formed by positive deviation from Raoult's law? Give an example.


The solutions that do not obey Raoult’s law over the entire range of concentration are known as non-ideal solutions. They have vapour pressures either higher or lower than those predicted by Raoult’s law. If the vapour pressure is higher, then the solution is said to exhibit a positive deviation from Raoult’s law.

 A mixture of ethanol and acetone is an example of a solution that shows a positive deviation from Raoult’s law.

 In case of solutions showing positive deviations, absorption of heat takes place that  mixH has a positive sign.

 OR

Azeotropes are the binary mixtures of solutions that have the same composition in liquid and vapour phases and that have constant boiling points.

 A minimum-boiling azeotrope is formed by solutions showing a large positive deviation from Raoult’s law at a specific composition.

 Example: An ethanol–water mixture containing approximately 95% ethanol by volume

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246.

3.9 g of benzoic acid dissolved in 49 g of benzene shows a depression in freezing point of 1.62 K. Calculate the van't Hoff factor and predict the nature of solute (associated or dissociated).


(Given: Molar mass of benzoic acid = 122 g mol-1, Kf for benzene = 4.9 K kg mol-1

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247.

Calculate the mass of compound (molar mass = 256 g mol-1) to be dissolved in 75 of benzene to lower its freezing point by 0.48 K (Kf= 5.12 kg mol-1 )

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248.

Define an ideal solution and write one of its characteristics.

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249.

18 g of glucose, C6H12O6 (Molar Mass = 180 g mol-1) is dissolved in 1 kg of water in a saucepan. At what temperature will this solution boil? 

 (Kb for water = 0.52 K kg mol-1, boiling point of pure water = 373.15 K)

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250.

Determine the osmotic pressure of a solution prepared by dissolving 2.5 x 10-2 g of K2SO4 in 2L of water at 250C, assuming that it is completely dissociated. 

(R = 0.0821 L atm K-1   mol-1, Molar mass of K2SO4 = 174 g mol-1)

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