The freezing point of a 0.05 molal solution of a non- electrolyte in water is
-0.093° C
1.86°C
0.93° C
0.093°C
Solutions A, B, C and D are respectively 0.1 M glucose, 0.05 M NaCl, 0.05 M BaCl2 and 0.1 M AlCl3. Which one of the following pairs is isotonic?
A and B
B and C
A and D
A and C
Copper is a divalent metal. The value of its electrochemical equivalent is 3.29 × 10-4 g. Its atomic mass is
31.74 g
63.5 g
126.9 g
15.87 g
The vapour pressure of benzene at a certain temperature is 640 mm of Hg. A non-volatile and non-electrolyte solid weighing 2.175 g is added to 39.08 g of benzene. If the vapour pressure of the solution is 600 mm of Hg, what is the molecular weight of solid substance ?
49.50
59.60
69.60
79.82
Which of the following solutions will have highest boiling point ?
0.1 M FeCl3
0.1 M BaCl2
0.1 M NaCl
0.1 M urea (NH2CONH2)
Maximum depression in freezing point is caused by
potassium chloride
sodium sulphate
magnesium sulphate
magnesium carbonate
Which of the following is not a colligative property?
Elevation in boiling point
Lowering of vapour pressure
Osmotic pressure
Freezing point
34.2 g of cane sugar is dissolved in 180 g of water. The relative lowering of vapour pressure will be
0.0099
1.1597
0.840
0.9901
According to Hess's law, the heat of reaction depends upon
initial condition of reactants
initial and final conditions of reactants
intermediate path of the reaction
end conditions of reactants
Ratio of loss in solvent to gain in CaCl2 tube is
C.
Loss in the weight of solvent = p° - p
Gain in the weight of CaCl2 tube = p°