The depression in freezing point of 0.1 M aqueous solutions of HC

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541.

In countries nearer to polar region, the roads are sprinkled with CaCl2 .This is :

  • to minimise the wear and tear of the roads

  • to minimise the snow fall

  • to minimise pollution

  • to minimise the accumulation of dust on the road


542.

The solubility of a gas in water at 300 K under a pressure of 100 atm is 4 x 10-3 kg L-1. Therefore, the mass of the gas in kg dissolved 250 mL of water under a pressure of 250 atm at 300 K is :

  • 2.5 x 10-3

  • 2.0 x 10-3

  • 1.25 x 10-3

  • 5.0 x 10-3


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543.

The depression in freezing point of 0.1 M aqueous solutions of HCl, CuSO4 and K2SO4 are in the ratio

  • 1 : 1 : 1.5

  • 1 : 2 : 3

  • 1 : 1 : 1

  • 2 : 4 : 3


A.

1 : 1 : 1.5

The depression in freezing point is calculated by the expression:

Tf = iKfm 

(where, T = depression in freezing point; i = vant hoff factor; K = constant; M = molarity of the solution)

Thus, Tf  i (as concentration is same for all solutions)

Let us consider that all compounds dissociate 100% (as i depends on the no. of total no. of ions that the molecules will produce on being dissociated ).

HCl will give 2 ions H+ and Cl-. Hence, its vant hoff factor is 2.

CuSO4 will give 2 ions Cu2+ and SO42-. Hence, its vant hoff factor is 2.

K2SO4 will give 3 ions, two K+ ions and one SO42-. Hence, its vant hoff factor is 3.

Therefore, the ratio of depression of freezing point will be the ratio of their vant hoff factor because the molarity is same for all three solution. The ratio will be 2 : 2 : 3. Further divided, the ratio will be 1 : 1 : 1.5


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544.

Which of the following pairs of substances cannot exist together in solution?

  • Na2CO3 + NaOH

  • NaHCO3 + Na2CO3

  • NaHCO3 + NaOH

  • NaOH + HCl


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545.

Assertion : Azeotropic mixtures are formed only by non-ideal solutions and they may have boiling points either greater than both the components or lesser than both the components.

Reason : The composition of the vapour phase is same as that ofthe liquid phase of an azeotropic mixture.

  • If both assertion and reason are true and reason is the correct explanation of assertion

  • If both assertion and reason are true but reason is not the correct explanation of assertion.

  • If assertion is true but reason is false

  • If both assertion and reason are false.


546.

Large difference in boiling points is observed in

  • N and P

  • P and As

  • As and Sb

  • Sb and Bi


547.

Arrange the given compounds in decreasing order of boiling points.

I. CH3CH2CH2CH2Br

II. C(CH3)3Br

III. CH3-CH2-CH(CH3)-Br

  • I > III > II

  • II > I > III

  • I > II > III

  • III > I > II


548.

Two elements A and B form compounds of formula AB2 and AB4. When dissolved in 20.0 g of benzene 1.0 g of AB2 lowers freezing point by 2.3°C whereas 1.0 g of AB4 lowers freezing point by 1.3°C. The Kf for benzene is 5.1. The atomic masses of A and B are

  • 25, 42

  • 42, 25

  • 52, 48

  • 48, 52


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549.

The freezing point of a solution containing 0.2 g of acetic acid in 20.0 g benzene is lowered by 0.45°C. The degree of association of acetic acid in benzene is (Assume acetic acid dimerises in benzene and Kf for benzene = 5.12K kg mol-1) Mobserved of acetic acid =  113.78

  • 94.5%

  • 54.9%

  • 78.2%

  • 100%


550.

60 g of urea is dissolved in 1100 g solution. To keep Tf/Kf as 1 mol kg-1 water separated in the form of ice is :

  • 40 g

  • 60 g

  • 100 g

  • 200 g


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