Assertion : Azeotropic mixtures are formed only by non-ideal solu

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541.

In countries nearer to polar region, the roads are sprinkled with CaCl2 .This is :

  • to minimise the wear and tear of the roads

  • to minimise the snow fall

  • to minimise pollution

  • to minimise the accumulation of dust on the road


542.

The solubility of a gas in water at 300 K under a pressure of 100 atm is 4 x 10-3 kg L-1. Therefore, the mass of the gas in kg dissolved 250 mL of water under a pressure of 250 atm at 300 K is :

  • 2.5 x 10-3

  • 2.0 x 10-3

  • 1.25 x 10-3

  • 5.0 x 10-3


543.

The depression in freezing point of 0.1 M aqueous solutions of HCl, CuSO4 and K2SO4 are in the ratio

  • 1 : 1 : 1.5

  • 1 : 2 : 3

  • 1 : 1 : 1

  • 2 : 4 : 3


544.

Which of the following pairs of substances cannot exist together in solution?

  • Na2CO3 + NaOH

  • NaHCO3 + Na2CO3

  • NaHCO3 + NaOH

  • NaOH + HCl


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545.

Assertion : Azeotropic mixtures are formed only by non-ideal solutions and they may have boiling points either greater than both the components or lesser than both the components.

Reason : The composition of the vapour phase is same as that ofthe liquid phase of an azeotropic mixture.

  • If both assertion and reason are true and reason is the correct explanation of assertion

  • If both assertion and reason are true but reason is not the correct explanation of assertion.

  • If assertion is true but reason is false

  • If both assertion and reason are false.


B.

If both assertion and reason are true but reason is not the correct explanation of assertion.

Non-ideal solutions with positive deviation i.e., having more vapour pressure than expected, boil at lower temperature while those with negative deviation boil at higher temperature than those of the components.


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546.

Large difference in boiling points is observed in

  • N and P

  • P and As

  • As and Sb

  • Sb and Bi


547.

Arrange the given compounds in decreasing order of boiling points.

I. CH3CH2CH2CH2Br

II. C(CH3)3Br

III. CH3-CH2-CH(CH3)-Br

  • I > III > II

  • II > I > III

  • I > II > III

  • III > I > II


548.

Two elements A and B form compounds of formula AB2 and AB4. When dissolved in 20.0 g of benzene 1.0 g of AB2 lowers freezing point by 2.3°C whereas 1.0 g of AB4 lowers freezing point by 1.3°C. The Kf for benzene is 5.1. The atomic masses of A and B are

  • 25, 42

  • 42, 25

  • 52, 48

  • 48, 52


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549.

The freezing point of a solution containing 0.2 g of acetic acid in 20.0 g benzene is lowered by 0.45°C. The degree of association of acetic acid in benzene is (Assume acetic acid dimerises in benzene and Kf for benzene = 5.12K kg mol-1) Mobserved of acetic acid =  113.78

  • 94.5%

  • 54.9%

  • 78.2%

  • 100%


550.

60 g of urea is dissolved in 1100 g solution. To keep Tf/Kf as 1 mol kg-1 water separated in the form of ice is :

  • 40 g

  • 60 g

  • 100 g

  • 200 g


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