Calculate the mass of nitrogen supplied to the soil by 5Kg of urea [CO(NH2)2]?
The formula for urea is.
The molar mass for urea is 14x 2+1x 4+12+16= 60 g/mole.
In this 60 g of urea, nitrogen has a mass of 28 g.
So by simple proportion in 5 kg of urea,
nitrogen has a mass =
20 mL solution of 0.1 M ferrous sulphate was completely oxidised using a suitable oxidising agent. What is the number of electrons exchanged?
1.204 x 1022
193
1930
1.204 x 1021