20 mL solution of 0.1 M ferrous sulphate was completely oxidised

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232.

20 mL solution of 0.1 M ferrous sulphate was completely oxidised using a suitable oxidising agent. What is the number of electrons exchanged?

  • 1.204 x 1022

  • 193

  • 1930

  • 1.204 x 1021


D.

1.204 x 1021

During oxidation of FeSO4, Fe2+ ion is oxidises into Fe3+

Fe2+ → Fe3+ + e-

i.e., 1e- is transferred from FeSO4 , i.e., from 1 molecule of Fe2+  ion.

Now, molarity of FeSO4 solution = 0.1 M and volume of solution = 20 mL = 201000LNumber of moles= 0.1 ×201000=0.002 In 1 mole FeSO4 number of molecules= 6.022 × 1023In 0.002 mol FeSO4 , number of molecules = 6.022 × 1023 × 0.002 = 1 × 1.204 ×1021Number of electrons transferred     = 1 × 1.204 ×1021     


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