Commercial sample of H2O2 is labeled as 10 V. Its % strength is n

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271.

Commercial sample of H2O2 is labeled as 10 V. Its % strength is nearly

  • 3

  • 6

  • 9

  • 12


A.

3

10 V H2O2 means 1L of this solution will produce 10 L O2 at STP   2H2O2 2H2O + O268 g                             22.4 L at STP 22.4 L of O2  is obtained from H2O2 = 68g10L of O2 will be obtained from                   H2O2 =6822.4×10 = 30.36 g 1000 mL of the given solution contains 30.36 g H2O2 and 100 mL of the given solution contains               30.36 x 1001000= 3.03 g H2O2 Thus, % strength of H2O2  is 3.03 ( 3).


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272.

The system that contains the maximum number of atoms is

  • 4.25 g of NH3

  • 8 g of O2

  • 2g of H2

  • 4g of He


273.

The volume of ethyl alcohol ( density 1.15 g/cc) that has to be added to prepare 100 cc of 0.5 M ethyl alcohol solution in water is 

  • 1.15 cc

  • 2 cc

  • 2.15 cc

  • 2.30 cc


274.

Which one of the following is wrong about molecularity of a reaction?

  • It may be whole number or fractional

  • It is calculated from reaction mechanism

  • It is the number of molecules of the reactants taking part in a single step chemical reaction

  • It is always equal to the order of elementary reaction


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275.

The amount of the heat released when 20 mL 0.5 M NaOH is mixed with 100 mL 0.1 M HCl is × kJ. The heat of neutralisation is

  • -100 x kJ/mol

  • -50 x kJ/mol

  • + 100 x kJ/mol

  • +50 x kJ/mol


276.

2 g of metal carbonate is neutralised completely by 100 mL of 0.1 N HCl. The equivalent weight of metal carbonate is

  • 50

  • 100

  • 150

  • 200


277.

If the molecular wt. of Na2SOand I2 are M1 and Mrespectively then what will be the equivalent weight of Na2SO3 and I2 in the following reaction?

2S2O32- + I2 → S4O62- + 2I-

  • M1, M2

  • M1, M2 /2

  • 2M1, M2

  • M1, 2M2


278.

The normality of 30 volume H2O2 is

  • 2.678 N

  • 5.336 N

  • 8.034 N

  • 6.685 N


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279.

The weight of oxalic acid that will be required to prepare a 1000 mL (N/20) solution is

  • 126/100 g

  • 63/40 g

  • 63/20 g

  • 126/20 g


280.

Gaseous benzene reacts with hyodrogen gas in presence of a nickel catalyst to form gaseous cyclohexane according to the reaction, 

C6H6 (g) + 3H2 (g) → C6H12 (g)

A mixture of C6H6 and excess H2 has a pressure of 60 mm of Hg in an unknown volume. After the gas had been passed over a nickel catalyst and all the benzene converted to cyclohexane, the pressure of the gas was 30 mm of Hg in the same volume at the same temperature. The fraction of C6H6 (by volume) present in the original volume is

  • 1/3

  • 1/4

  • 1/5

  • 1/6


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