64 g of an organic compound contains 24 g of carbon, 8 g of hydrogen and the rest oxygen. The empirical formula of the compound is
CH2O
C2H4O
CH4O
C2H8O
1f 20 mL of 0.4 N NaOH solution completely neutralises 40 mL of a dibasic acid, the molarity of the acid solution is
0.1 M
0.2 M
0.3 M
0.4 M
An organic compound containing C, H and N gives the following on analysis : C = 40%, H = 13.33% and N = 46.67%. What would be its empirical formula?
C2H7N
C2H7N2
CH4N
CH3N
How many moles of O2 can be obtained by electrolysis of 90 g H2O?
5.0 mol
0.5 mol
2.5 mol
0.25 mol
An organic compound A contains 20% C, 46.66% N and 6.66% H. It gives NH3 gas on heating with NaOH. A can be
CH3CONH2
C6H5CONH2
NH2CONH2
CH3NHCONH2
The empirical formula of a compound is CH2. One mole of this compound has a mass 42g. Its molecular formula is
C3H6
C2H6
CH2
C2H2
A.
C3H6
Empirical formula mass of CH2 = 12 + 2 = 14
Molecular mass = 42
Then, molecular formula = (empirical formula)
= (CH2)3
= C3H6
Aqueous solutions of hydrogen sulphide and sulphur dioxide when mixed together, yield
sulphur trioxide and water
hydrogen and sulphurous acid
sulphur and water
hydrogen peroxide and sulphur