3 g of oxide of a metal is converted to chloride completely and it yielded 5 g of chloride. The equivalent weight of metal is
12
20
33.25
2.325
4.9 g of H2SO4 is present in 100 mL solution. The molarity and normality of the solution will be
Molarity = 1M, Normality= 0.5N
Molarity = 1M, Normality= 0.25N
Molarity = 0.5M, Normality= 1N
Molarity = 2M, Normality= 3N
0.0833 mole of a carbohydrate of empirical formula CH2O contains 1.00 g of hydrogen. The molecular formula of the carbohydrate is.
C5H10O5
C3H4O3
C12H22O11
C6H12O6
When 50cm3 of 0.2N H2SO4 is mixed with 50 cm3 of 1N KOH, the heat liberated is
11.46 kJ
57.3 kJ
573 kJ
573 J
Heat liberated with 100 mL of 1 N NaOH is neutralised by 300 mL of 1 N HCl
11.56 kJ
5.73 kJ
22.92 kJ
17.19 kJ
A solution contains 1.2046 x 1024 hydrochloric acid molecules in one dm3 of the solution. The strength of the solution is
6N
2N
4N
8N
4g of copper was dissolved in concentrated nitric acid. The copper nitrate solution on strong heating gave 5 g of its oxide. The equivalent weight of copper is
23
32
12
20
The volume of water to be added to to prepare 500 mL of solution is
450 mL
100 mL
45 mL
400 mL
D.
400 mL
Let, x mL of HCl are taken, then
N1V1 = N2V2
x = 100 mL
Hence, water needed to add = 500 - 100 = 400 mL
The equivalent weight of a certain trivalent element is 20. Molecular weight of its oxide is
152
56
168
68
What is the volume of "20 volume H2O2" required to get 5000 cm3 of oxygen at STP?
250 cm3
50 cm3
100 cm3
125 cm3