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631.

If molecular weight of KMnO₄ is M, then its equivalent weight in acidic medium would be

632.

The volume of oxygen necessary for the complete combustion of 20 L of propane is :

180 atm

Number of moles of N₂ = $\frac{56}{28}$ = 2

Number of moles of CO₂ = $\frac{44}{44}$ = 1

Number of moles of CH₄ = $\frac{16}{16}$ = 1

$∴$ Total number of moles = 2 + 1 + 1 = 4

$∴$ Mole fraction of CH₄ = $\frac{1}{4}$

Therefore,

Partial pressure of CH₄ = mole fraction of CH₄ × total pressure

= $\frac{1}{4}$ × 720

= 180 atm

634.

20 volume H₂O₂ solution has a strenght of about

635.

74.5 g of a metallic chloride contains 35.5 g of chlorine, the quivalent weight of the metal is