A gas such as carbon monoxide would be most likely to obey the ideal gas law at
high temperatures and low pressures
low temperatures and high pressures
high temperatures and high pressures
high temperatures and high pressures
A bubble of air is underwater at temperature 15o C and the pressure 1.5 bar. If the bubbles rises to the surface where the temperature is 25o C and the pressure is 1.0 bar, what will happen to the volume of the bubble?
Volume will become greater by a factor of 1.6
Volume will become greater by a factor of 1.1
Volume will become smaller by a factor of 0.70
Volume will become smaller by a factor of 0.70
The pressure exerted by 6.0 g of methane gas in a 0.03 m3 vessel at 129o C is (Atomic masses C = 12.01, H = 1.01 and R = 8.314 JK-1 mol-1)
215216 Pa
13409 Pa
41648 Pa
41648 Pa
What is the dominant intermolecular force or bond that must be overcome in converting liquid CH3OH to a gas?
Hydrogen bonding
Dipole-dipole interaction
Covalent bonds
Covalent bonds
If a gas expands at constant temperature, it indicates that
the kinetic energy of molecules decrease
the pressure of the gas increases
the kinetic energy of molecules remains the same
the kinetic energy of molecules remains the same
What volume of oxygen gas (O2) measured at 0oC and 1 atm, is needed to burn completely 1 L of propane gas (C3H8) measured under the same conditions?
7 L
6 L
5 L
5 L
20-litre container at 400 K contains CO2(g) at pressure 0.4 atm and an excess of SrO (neglect the volume of solid SrO). The volume of the containers is now decreased by moving the movable piston fitted in the container. The maximum volume of the container, when pressure of CO2 attains its maximum value, will be
Given that: SrCO3 ⇌ SrO(s) + CO2(g) kp = 1.6 atm)
5 litre
10 litre
8 litre
8 litre
A.
5 litre
Max. the pressure of CO2= Pressure of CO2 at equilibrium
For reaction, SrCO3 ⇌ SrO(s) + CO2(g)
Kp= PCO2 = 1.6 atm = maximum pressure of CO2
Volume Container at this stage,
V= nRT/P .... (i)
Since container is sealed and reaction was not earlier at equilibrium
therefore, n = constant
n= Pv/RT .... (ii)
from equation (i) and (ii) we get
V = (0.4 x 20)/RT = 5 Litre
The compressibility of a gas is less than unity at STP, therefore,
Vm > 22.4 L
Vm < 22.4 L
Vm = 22.4
Vm = 44.8 L
Temperature of a gas is t K. What would be the temperature at which volume and pressure, both will reduced to half of the initial values?
At 27°C, one mole of an ideal gas is compressed isothermally and reversibly from a pressure of 2 atm to 10 atm. Choose the correct option from the following
Change in internal energy is positive
Heat is negative
Work done is - 965.84 cal
All are incorrect