Among the following set of quantum numbers, the impossible set is

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 Multiple Choice QuestionsMultiple Choice Questions

551.

Magnesium reacts with an element (X) to form an ionic compound. If the ground state electronic configuration of (X) is 1s2 2s2 2p3, the simplest formula for this compound is

  • Mg2X3

  • MgX2

  • Mg3X2

  • Mg2X


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552.

Among the following set of quantum numbers, the impossible set is

  • n l m s
    3 2 -3 -1/2
  • n l m s
    4 0 0 1/2
  • n l m s
    5 3 0 -1/2
  • n l m s
    3 2 -2 1/2


A.

n l m s
3 2 -3 -1/2

Principal quantum number = n
Azimuthal quantum number = l = 0 to (n-1)
Magnetic quantum number = m = -l to +1
Spin quantum number = s = +1/2 or -1/2
Now,

(i) In first option the given values are,

n=3; l=2; m=-3; s=-1/2

So according to Azimuthal quantum number

l = 0 to (n-1) = 0 to 2 = here it is 2 which is permissible

m = -l to +l = -2 to +2 = here it is 3 which is  not permissible

s = +1/2 or -1/2 = here it is -1/2 whch is permissible

(ii) In the second option given values are,

n = 4; l = 0, m = 0; s= 1/2

So according to Azimuthal quantum number

l = 0 to (n-1) = 0 to 3 = here it is 0 which is permissible

m =-l to +l = -3  to +3 = here it is 0 which is permissible

s = +1/2 or -1/2 = here it is 1/2 whch is permissible

(iii) In the third option given values are,

n =5; l = 3; m= 0; s= -1/2

So according to Azimuthal quantum number

l = 0 to (n-1) = 0 to 4 = here it is 3 which is permissible

m = -l to +l = -4 to +4 = here it is 0 which is permissible

s = +1/2 or -1/2 = here it is -1/2 whch is permissible

(iv) it the forth option given values are,

n=3; l =2; m=-2; s = 1/2

So according to Azimuthal quantum number

l = 0 to (n-1) = 0 to 2 = here it is 2 which is permissible

m = -l to +l = -2 to +2 = here it is 2 which is permissible

s = +1/2 or -1/2 = here it is -1/2 whch is permissible


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553.

Match the type of series given in Column I with the wavelength range given in Column II and choose the correct option.
Column I Column II
A Lyman 1. Ultraviolet
B. Paschen 2. Near-infrared
C. Balmer 3. Far Infrared
D. Pfund 4. Visible

  • A B C D
    1 2 4 3
  • A B C D
    4 3 1 2
  • A B C D
    3 1 2 4
  • A B C D
    4 3 2 1

554.

The electrons identified by quantum numbers n and l, are as follows

  1. n =4, l=1
  2. n = 4, l = 0

  3. n =3, l= 2

  4. n = 3, l = 1

If we arrange them in order of increasing energy, i.e., from lowest to highest, the correct order is

  • IV<II<III<I

  • II<IV<I<III

  • I < III < II < IV

  • III < I < IV < II


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555.

What will be the number of waves formed by a Bohr electron in one complete revolution in its second orbit?

  • Three

  • Two

  • One

  • Zero


556.

Match the particle with its characteristic
Column I Column II
A. α-particle p. Slow moving
B. Isobar q. High penetration power
C. γ- ray r. Same atomic mass
D. β- particle s. consists of electron

  • A - p; B - r; C - q; D - s

  • A - p; B - q; C - r; D - s

  • A - r; B - s; C - p; D - q

  • A - s; B - r; C - p; D - q


557.

Highest energy will be absorbed to eject out the electron in the configuration.

  • 1s22s22p1

  • 1s22s22p3

  • 1s22s22p2

  • 1s22s22p4


558.

If n = 6, the correct sequence for filling of electrons will be

  • ns (n - 1)d (n - 2)f np

  • ns (n - 2)f np (n - 1)d

  • ns np (n - 1)d (n - 2)f

  • ns (n - 2)f (n - 1)d np


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559.

An electron is moving in Bohr's fourth orbit. Its de-Broglie wave length is λ. What is the circumference of the fourth orbit?

  • 2λ

  • 2λ

  • 4λ 

  • 4λ


560.

The Vividh Bharti Station of All India Radio, Delhi, broadcasts on a frequency of 1,368 kHz (Kilohertz). Calculate the wavelength (λ) of the electromagnetic radiation emitted by transmitter. Which part of the electromagnetic spectrum does it belong to?

  • 319.4 m and X-rays

  • 319.4 m and radiowave

  • 219.3 m and microwave

  • 219.3 m and radiowave


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