Assertion: The absorption spectrum consists of some bright lines separated by dark spaces.
Reason: Emission spectrum consists of dark lines.
If both assertion and reason are true and reason is a correct explanation of the assertion.
If both the assertion and reason are true but the reason is not a correct explanation of the assertion.
If the assertion is true but the reason is false.
If both the assertion and reason are false.
11Na24 1s radioactive and it decays to:
9F20 and -particles
13Al24 and positron
11Na23 and neutron
12Mg24 and -particles
Which of the following does not represent the mathematical expression for the Heisenberg uncertainty principle?
x .p h/(4)
x . h/(4)
. h/(4)
. h/(4)
During the emission of a positron from a nucleus, the mass number of the daughter element remains the same but the atomic number
is decreased by 1 unit
is decreased by 2 units·
is increased by 1 unit
remains unchanged
β- emission is always accompained by
formation of antineutrino and α-particle
emission of α-particle and γ-ray
formation of antineutrino and γ-ray
formation of antineutrino and positron
The value of Planck's constant is 6.63 x 10-34 Js. The speed of light is 3 x 1017 nms-1. Which value is closest to the wavelength in nanometer of a quantum of light with frequency of 6 x 1015 s-1?
10
25
50
75
What is the maximum numbers of electrons that can be associated with the following set of quantum numbers? n = 3, l = 1 and m =-1.
10
6
4
2
An atomic nucleus having low n/p ratio tries to find stability by
the emission of an α-particle
the emission of a positron
capturing an orbital electron (K-electron capture)
emission of β -particle
B.
the emission of a positron
Emission of a positron results in the conversion of a proton into neutron, along with the release of neutrino. Thus, the number of protons decreases and of neutron increases, i.e., n/p ratio increases and the nuclei becomes stable.
(32Ge76, 34Se76) and (14Si30, 16S32) are examples of
isotopes and isobars
isobars and isotones
isotones and isotopes
isobars and isotopes
98Cf246 was formed along with a neutron when an unknown radioactive substance was bomabrded with 6C12. The unknown substance is
91Pa234
90Th234
92U235
92U238