Suppose the mass of a single Ag-atom is m. Ag metal crystallises

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

Advertisement

501.

Suppose the mass of a single Ag-atom is m. Ag metal crystallises in fcc lattice with unit cell of length a. The density of Ag metal in terms of a and 'm' is

  • 4ma3

  • 2ma3

  • ma3

  • m4a3


A.

4ma3

According to the question,

Mass of single atom = m 

Unit cell length = a

Total atoms present per unit cell of fcc lattice = 4

Therefore, mass of unit cell becomes 4m

Volume of unit cell = a3

Density = Mass of unit cellVolume of unit cell = 4ma3


Advertisement
502.

Crystalline solids have

  • short range order

  • long range order

  • anisotropic distribution

  • All of these.


503.

The number of carbon atoms per unit cell of diamond unit cell is

  • 4

  • 8

  • 6

  • 1


504.

A metal has a fcc lattice. The edge length of the unit cell is 404 pm. The density of the metal is 2.72 g cm3. The molar mass of the metal is (NA  vogadro's constant = 6.02x 1023 mol-1).

  • 40 g mol-1

  • 30 g mol-1

  • 27g mol-1

  • 20 g mol-1


Advertisement
505.

What is the co-ordination number of body centred cube ?

  • 8

  • 6

  • 4

  • 12


506.

A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is :

  • C3A2

  • C3A4

  • C4A3

  • C2A3


Advertisement