Why does Zr and Hf exhibit similar properties?
Zr and Hf exhibit similar properties due to lanthanoid contractin. Electrons present in f subshell didn't do good shielding due to which with the increasing atomic number or increasing effective nuclear charge size gets constricted and size of Halfenium and Zirconium becomes almost equal.
2(40) = [Kr]364d2 5s2, Hf(72) = [Xe]54 4f14 5d2 6s2
Why is the following electronic configuration not correct for the ground state of Mo atom? (at. no. = 42).
1s2 2s2 2p6 3s23p63d10 4s2 4p6 4d4 5s2.