Ti2+, V2+ and Cr2+are strong reducing agents. Why? from Chem

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 Multiple Choice QuestionsShort Answer Type

41.

Why V and Mn has E° value more than E° value of Cr?

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42. What may be the stable oxidation state of the transition elements with the following d-electron configurations in the ground state of their atoms 3d3, 3d5, 3d8 and 3d4?
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43. Transition metals tend to be less reactive. Explain
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44.

Compare qualitatively the first and second ionisation potentials of copper and zinc. Explain the above observation.

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45.

What does the E° value of M3+/M2+ show for Mn3+ and Co3+ (+ 1.57 and 1.97 V respectively)?

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46. Ti2+, V2+ and Cr2+are strong reducing agents. Why?


The E° value of M2+/M for Ti2+, V2+ and Cr2+ are negative which shows that they are strong reducing agents.
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47. Give a reaction to show that Cr2+ acts as a reducing agent.
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48. Why is the E° value for Mn3+/Mn2+ higher than that of Cr3+/ Cr2+ (or Fe3+/Fe2+)?
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49. How would you account for the increasing oxidising power in the series VO2+< Cr2O72–  < MnO4–?
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50. The ionisation enthalpies of Cr and Cu are larger than their neighbours. Why?
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