(a) Comment on the following tendencies of transition elements of first series:
(i) They exhibit variable oxidation states.
(ii) They easily form alloys.
(iii) They often act as catalyst.
(b) State the different characteristic of actinoids and lanthanoids which places them in f-block elements.
(c) How many unpaired electrons are there in Ni2+(aq)?
Account for the following:
(a) Transition elements have high boiling point and high enthalpy of atomisation.
(b) Zn, Cd, Hg are normally not regarded as transition elements.
(c) Transition metals generally form alloys with other transition metals.
(d) Transition metals form a number of interstitial compounds.
(e) Ni2+ compounds are thermodynamically more stable than Pt2+ compounds.
(i) What are inner transition elements? Write their general electronic configuration.
(ii) The chemistry of the actinoid elements is not so smooth as that of the Lanthanoids. Justify this statement by giving some examples from the oxidation state of these elements?
Describe the general characteristics of the transition elements with special reference to their tendency to
(i) exhibit paramagnetism, (ii) form complex compounds, (iii) their catalytic behaviour.
What are the transition elements? Write two characteristics of the transition elements ?
How would you account for the following?
Actinoid contraction is greater than lanthanoid contraction.
Which metal in the first transition series (3d series) exhibits + 1 oxidation state most frequently and why?
Which of the following cations are coloured in aqueous solutions and why?
Sc3+, V3+, Ti4+, Mn2+ (Atomic number Sc = 21, V = 23, Ti = 22, Mn = 25)
The colour of cations is dependent on the number of unpaired electrons present in d-orbital. The electronic configuration of the following cations is as follows:
Sc (Atomic number 21) = 3d1 4s2 and Sc3+ = 3d0 4s0. As d-orbital is empty, it is colourless.
V (Atomic number 23) = 3d3 4s2 and V3+ = 3d2 4s0. As d-orbital is having 2 unpaired electrons, it undergoes d-d transition and shows green colour
Ti = (Atomic number 22) = 3d2 4s2 and Ti4+ = 3d0 4s0. As d-orbital is empty, it is colourless
Mn = (Atomic number 25) = 3d5 4s2 and Mn2+ = 3d5 4s0. As d-orbital is having 5 unpaired electrons, it shows pink color.