How can the lattice enthalpy of an ionic NaCl be determined by u

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 Multiple Choice QuestionsShort Answer Type

231.

What are important consequences of lattice enthalpies?

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 Multiple Choice QuestionsLong Answer Type

232. What is Born-Haber cycle? How can we obtain lattice enthalpy of a solid with its help? 
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233.

How can the lattice enthalpy of an ionic NaCl be determined by using Born-Haber cycle?


Formation of NaCl may be done by two different methods:
(a) Indirect method
(b) Direct method.

(a) Indirect method: Various terms involved are:

  Since enthalpy is required for the process (endothermic), therefore   is taken as a positive quantity.

(ii) 
The process is endothermic, therefore   is taken as a positive quantity. 


Since the process is endothermic, therefore, ionisation enthalpy is taken as a positive quantity.


Since the process is exothermic, therefore electron gain enthalpy is taken as a negative quantity. 


Enthalpy is released in this process i.e. process is exothermic, therefore   is always taken as a negative quantity. 

(b) Direct method:  Let   be the enthalpy of formation of 1 mol of NaCl(s) from its constituent species. 
               

According to Hess's law, the enthalpy of formation of one mole of sodium chloride should be the same irrespective of the fact whether it takes place directly in one step.
(Direct method) or through a number of steps (Indirect method).



where  is the enthalpy change for lattice formation from
  

The reverse of the above equation i.e.
  

defines the lattice enthalpy of NaCl.
Thus by using the Born- Haber cycle,  one can determine the lattice enthalpy of an ionic compound.

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234.

Calculate the lattice enthalpy of KCl crystal from the following data:

Sublimation enthalpy of pottasium (K) = +89 kJ mol-1
Dissociation enthalpy of 1 half Cl subscript 2 left parenthesis straight g right parenthesis
                                          = +122 kJ mol-1
Ionisation enthalpy of K(g) +425 kJ mol-1
Electron gain enthalpy of Cl(g) = -355 kJ mol-1
Enthalpy of formation of KCl left parenthesis increment subscript straight r straight H degree right parenthesis space equals space minus 438 space kJ space mol to the power of negative 1 end exponent



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235.

Calculate the lattice enthalpy of LiF, given that the enthalpy of
(i) sublimation of lithium is 155.2 kJ mol–1
(ii) dissociation of 1/2 mol of F2is 75.3 kJ
(iii) ionization of lithium is 520 kJ mol–1
(iv) electron gain of 1 mol of F(g) is –333 kJ
(v) ∆f H0 ∆fH0 overall is –795 kJ mol–1

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 Multiple Choice QuestionsShort Answer Type

236.

Calculate the lattice enthalpy of MgBr2 from the given data. The enthalpy of formation of MgBr2 according to the reaction

Mg left parenthesis straight s right parenthesis space plus space Br subscript 2 left parenthesis straight l right parenthesis space space space rightwards arrow space space MgBr subscript 2 left parenthesis straight s right parenthesis semicolon space increment subscript straight f straight H to the power of 0 space equals space minus 524 space kJ space mol to the power of negative 1 end exponent
CH subscript 1 superscript 0 space for space Mg left parenthesis straight s right parenthesis space space rightwards arrow space space Mg to the power of 2 plus end exponent left parenthesis straight g right parenthesis space plus space 2 straight e to the power of minus space equals space plus 2187 space kJ space mol to the power of negative 1 end exponent
increment straight H subscript 3 superscript 0 space for space Br subscript 2 left parenthesis straight l right parenthesis space space rightwards arrow space space space space Br subscript 2 left parenthesis straight g right parenthesis space equals space 31 space kJ space mol to the power of negative 1 end exponent
increment straight H subscript 4 superscript 0 space for space Br subscript 2 left parenthesis straight g right parenthesis space equals space 2 space Br left parenthesis straight g right parenthesis space equals space 193 space kJ space mol to the power of negative 1 end exponent
increment straight H subscript 5 superscript 0 space for space Br left parenthesis straight g right parenthesis space plus space straight e to the power of minus left parenthesis straight g right parenthesis space space rightwards arrow space space Br to the power of minus space equals space minus 331 space kJ space mol to the power of negative 1 end exponent
increment straight H subscript 6 superscript 0 space for space Mg to the power of 2 plus end exponent left parenthesis straight g right parenthesis space plus 2 Br to the power of minus left parenthesis straight g right parenthesis space space rightwards arrow space space space MgBr subscript 2 left parenthesis straight s right parenthesis space equals space ?

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 Multiple Choice QuestionsLong Answer Type

237. What do you understand by spontaneous and non-spontaneous processes? 
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238. Is ∆H the only criterion for the feasibility of a process ? Comment.
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239.

The tendency of a system to acquire a state of maximum randomness is the sole criterion for the spontaneity of a process. Comment.

 
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240. “Driving force is the overall tendency of a process to occur.” Comment on, the statement.
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