The enthalpy of vaporization of benzene is +35.3 kJ/mol at its bo

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

501.

When compared to ΔG° for the formation of Al2O3, the ΔG° for the formation of Cr2O3 is

  • higher

  • lower

  • same

  • unpredicted


502.

Consider the Born-Haber cycle for the formation of an ionic compound given below and identify the compound (Z) formed.

 

  • M+X-

  • M+X-(s)

  • MX

  • M+X-(g)


503.

For the reaction H2O (l)  H2O (g) at 373 K and 1 atm pressure

  • H = 0

  • E = 0

  • H = TS

  • H = E


504.

The enthalpy of formation of NH3 is - 46kJ mol-1. The enthalpy change for the reaction is-

2NH3 (g) → N2 (g) + 3H2 (g) 

  • +184 kJ

  • +23 kJ

  • +92 kJ

  • +46 kJ


Advertisement
505.

Enthalpy of vaporization of benzene is + 35.3 kJ mol-1at its boiling point, 80C. The entropy change in the transition of the vapour to liquid at its boiling point in [JK-1mol-1] is

  • -441

  • -100

  • +441

  • +100


506.

The amount of heat evolved when 500 cm3 of 0.1 M HCl is mixed with 200 cm3 of 0.2 M NaOH is

  • 2.292 kJ

  • 1.292 kJ

  • 0.292 kJ

  • 3.392 kJ


507.

During the adsorption of krypton on activated charcoal at low temperature.

  • ΔH > 0 and ΔS < 0

  • ΔH < 0 and ΔS < 0

  • ΔH > 0 and ΔS > 0

  • ΔH < 0 and ΔS < 0


508.

The amount of heat evolved when 500 cm3 of 0.1 M HCl is mixed with 200 cm3 of 0.2 M NaOH is

  • 2.292 kJ

  • 1.292 kJ

  • 22.9 kJ

  • 0.292 kJ


Advertisement
Advertisement

509.

The enthalpy of vaporization of benzene is +35.3 kJ/mol at its boiling point, 80°C. The entropy change in the transition of vapour to liquid at its boiling point is

  • -100

  • +100

  • +342

  • -342


A.

-100

H = +35.3 kJ/ mol

T = 80°C = 80 + 273 = 353 K

S = HT = +35.3353 = 0.1 kJ/ mol/ KS = 0.1 × 103 = 100 J/ mol/ K

Entropy change in the tranistion of vapour to liquid is negative, S = -100


Advertisement
510.

Based on the first law of thermodynamics, which one of the following is correct?

  • For an isothermal process, Q = + W

  • For an isochoric process, U = -Q

  • For an adiabatic process, U= -W

  • For a cyclic process, Q = -W


Advertisement