simplify a(a2 + a + 1) + 5 and find its values for (i) a = 0, (ii) a = 0, and (iii) a = -1.
Subtract: 3l(l – 4m + 5n) from 41(10n + 3m + 2l)
∵ 3l(l - 4m + 5n) = 3l x l - 31 x 4m +3l x 5n
= 3l2 - 12lm + 15ln
and 4l(10n - 3m + 21) = 4l x 10n - 4l x 3m +4l x 21
= 40ln - 12lm + 8l2
∴ 40ln - 12lm + 8l2
+ 3l2 - 12lm + 15ln
(-) (+) (-)
(40 - 15)ln + (12 - 12)lm + (8 -3)l2
= 25lm + (8 -3)l2
= 5l2 + 25ln