Trying to find the right answer to this..

When a = b ( each = y) (x + a)(x + b) = x 2 + (a + b) x + ab becomes (x + y)(x + y) = x 2 + (y +y)x + (y x y) = x 2 + (2y)x + y 2 = x 2 + 2yx + y 2 Yes it is the same as identity 1.

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.

Algebraic Expressions and Identities

Short Answer Type

81.

Simplify:

(x + y) (x²-xy + y²)

121 Views

82.

Simplify:

(1.5x - 4y) (1.5x + 4y + 3) - 4.5x + 12y

376 Views

83.

Simplify:

(a +b + c)(a + b + c)

128 Views

84.

Find the product of

(i) ( 3a + 4b) and (2a + 3b)

(ii) ( x - 4) and ( 2x +3)

107 Views

85.

Multiply : ( x - y) and ( 3x + 5y)

96 Views

86.

Multiply :

(i) (a + 7) and ( b -5)

(ii) ( a²+ 2b²)9 and ( 5a - 3b)

132 Views

87.

Simplify :

(i) (a + 7) (a²+ 3a + 5)

(ii) (a + b) (2a - 3b + c) - (2a - 3b)c

226 Views

88.

Verify Identity (IV), for a = 2, b = 3, x = 5.

235 Views

89.
Consider the special case of Identity (IV) with a = b, what do you get? Is it related to Identity (1)?

When a = b ( each = y)

(x + a)(x + b) = x²+ (a + b) x + ab becomes
(x + y)(x + y) = x²+ (y +y)x + (y x y)
                     = x²+ (2y)x + y²
                     = x²+ 2yx + y²

                     Yes it is the same as identity 1.