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The identity IV is given by ( x + a) ( x+ b) = x 2 + (a + b)x + ab Replacing 'b' by (-a), we have: ( x + a) ( x - a) = x 2 + [a + (-a)]x + [a x (-a)] = x 2 + [0]x + [-a 2 ] = x 2 + 0 + (-a 2 ) = x 2 -a 2

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Algebraic Expressions and Identities

Short Answer Type

91.
Consider the special case of Identity (IV) with b = –a. What do you get? It is related to Identity (III).

The identity IV is given by

    ( x + a) ( x+ b) = x²+ (a + b)x + ab

Replacing 'b' by (-a), we have:
               ( x + a) ( x - a) = x²+ [a + (-a)]x + [a x (-a)]
                                     = x²+ [0]x + [-a² ]
                                     = x²+ 0 + (-a²)
                                     = x²-a²

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92.

Use a suitable identity to get each of the following products.

(x + 3) ( x + 3)

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93.

Use a suitable identity to get each of the following products.

(2y + 5) (2y + 5)

106 Views

94.

Use a suitable identity to get each of the following products.

(2a - 7) (2a - 7)

121 Views

95.

Use a suitable identity to get each of the following products.

$space space space space space space space space space space space space space space space space space space space space open parentheses 3 a minus 1 half close parentheses open parentheses 3 a minus 1 half close parentheses$

92 Views

96.

Use a suitable identity to get each of the following products.

(1.1m - 0.41) (1.1m + 0.4)

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97.

Use a suitable identity to get each of the following products.

(a²+ b²) (-a² + b²)

117 Views

98.

Use a suitable identity to get each of the following products.

(6x - 7) (6x + 7)

122 Views

99.

Use a suitable identity to get each of the following products.

(-a + c) (-a + c)

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100.

Use a suitable identity to get each of the following products.

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