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Using the identity (x + a) (x + b) = x 2 + (a + b)x + ab we have (x + 3 ) (x + 3) = x 2 + ( 3 + 3)x + ( 3 x 3) = x 2 + 6x + 9

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Algebraic Expressions and Identities

Short Answer Type

91.

Consider the special case of Identity (IV) with b = –a. What do you get? It is related to Identity (III).

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92.
Use a suitable identity to get each of the following products.

(x + 3) ( x + 3)

Using the identity
(x + a) (x + b) = x²+ (a + b)x + ab

we have

(x + 3 ) (x + 3) = x²+ ( 3 + 3)x + ( 3 x 3)
= x² + 6x + 9

164 Views

93.

Use a suitable identity to get each of the following products.

(2y + 5) (2y + 5)

106 Views

94.

Use a suitable identity to get each of the following products.

(2a - 7) (2a - 7)

121 Views

95.

Use a suitable identity to get each of the following products.

$space space space space space space space space space space space space space space space space space space space space open parentheses 3 a minus 1 half close parentheses open parentheses 3 a minus 1 half close parentheses$

92 Views

96.

Use a suitable identity to get each of the following products.

(1.1m - 0.41) (1.1m + 0.4)

97 Views

97.

Use a suitable identity to get each of the following products.

(a²+ b²) (-a² + b²)

117 Views

98.

Use a suitable identity to get each of the following products.

(6x - 7) (6x + 7)

122 Views

99.

Use a suitable identity to get each of the following products.

(-a + c) (-a + c)

84 Views

100.

Use a suitable identity to get each of the following products.

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