Consider the special case of Identity (IV) with b = –a. What do you get? It is related to Identity (III).
Use a suitable identity to get each of the following products.
(1.1m - 0.41) (1.1m + 0.4)
Use a suitable identity to get each of the following products.
Using the identity, (a + b)2 = a2 + b2 + 2ab, we have