Simplify:
(ab + bc)2 - 2ab2c
(ab + bc)2 - 2ab2c = (ab)2 + 2(ab)(bc) + (bc)2 - 2ab2c
                         = a2b2 + 2ab2c + b2c2 - 2ab2c
                         = a2b2 + 0 + b2c2Â
                         = a2b2+ b2c2