Find the slope of the normal at the point (am3 , am2 ) to the curve a x2 = y3.
The equation of the curve is a x2 = y3
Differentiating both sides w.r.t. x, we get,
Find a point on the curve y = (x – 2)2 at which the tangent is parallel to the chord joining the points (2, 0) and (4, 4).
Find the equation of the tangent and normal to the curve y2 = 4ax at the point (at2, 2at).