Find the equation of the normal at the point (am2, am3) for the

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 Multiple Choice QuestionsShort Answer Type

81.

Show that the normal at any point 0 to the curve
x = a cosө + a ө sinө. y = a sin ө – a ө cos ө
is at a constant distance from the origin.

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82.

Find the equation of the tangent and normal to the given curves at the points given:
y = x2 at (0,0).

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83.

Find the equation of the tangent and normal to the given curves at the points given:
y2 = 4ax at (0, 0).

89 Views

84.

Find the equation of the tangent and normal to the given curves at the points given:
y = x3 at (1, 1)

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85.

Find the equation of the tangent and normal to the given curves at the points given:
y = x2 at (2, 8)

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 Multiple Choice QuestionsLong Answer Type

86.

Find the equation of tangent and normal to the hyperbola straight x squared over straight a squared minus straight y squared over straight b squared space equals space 1 space space space space at space the space point space space left parenthesis straight x subscript 0 comma space space space straight y subscript 0 right parenthesis

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 Multiple Choice QuestionsShort Answer Type

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87. Find the equation of the normal at the point (am2, am3) for the curve ay= x3.


The equation of the curve is a y2 = x3
Differentiating both sides w.r.t. x,
                      2 ay dy over dx space equals space 3 straight x squared. space space space space space space space space space space or space space space space space space dy over dx space equals space fraction numerator 3 straight x squared over denominator 2 ay end fraction

At left parenthesis am squared comma space space am cubed right parenthesis comma space space dy over dx space equals space fraction numerator 3 cross times space straight a squared straight m to the power of 4 over denominator 2 straight a cross times space am cubed end fraction space equals space fraction numerator 3 straight a squared straight m to the power of 4 over denominator 2 straight a squared straight m cubed end fraction space equals space 3 over 2 straight m
which is slope of tangent.
therefore space space space space slope space of space normal space space equals space fraction numerator 2 over denominator 3 straight m end fraction
therefore space space space space space the space equation space of space normal space at space left parenthesis am to the power of minus comma space space space am cubed right parenthesis space is
space space space space space space space space space space straight y minus am cubed space equals space minus fraction numerator 2 over denominator 3 straight m end fraction left parenthesis straight x minus am cubed right parenthesis space space space space space or space space space space space space 3 my minus 3 am to the power of 4 space equals space minus 2 straight x plus 2 am squared
or space space space space space 2 straight x plus 3 my minus 3 am to the power of 4 minus 2 am squared space equals space 0
or space space space space space space 2 straight x plus 3 my minus am squared left parenthesis 3 straight m squared plus 2 right parenthesis space equals space 0


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88.

Find the equation of the tangent and the normal to the curve straight x to the power of 2 over 3 end exponent plus straight y to the power of 2 over 3 end exponent space equals space 2 space space space at space space left parenthesis 1 comma space 1 right parenthesis.

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89. Find the equation of the tangent and normal to the curve y2 = 4ax at (at2, 2at)
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 Multiple Choice QuestionsLong Answer Type

90.

Find the equation of the tangent and normal to the curve
straight x equals space 1 minus cos space straight theta comma space space space space straight y space equals space straight theta space minus sin space straight theta space space space at space straight theta space equals space straight pi over 4

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