Prove that the function x2 – x + 1 is neither increasing nor

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 Multiple Choice QuestionsLong Answer Type

161.

Prove that straight y equals space fraction numerator 4 space sin space straight theta over denominator 2 plus cos space straight theta end fraction minus straight theta is an increasing function of straight theta in open square brackets 0 comma space straight pi over 2 close square brackets.

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162.

Find the intervals in which the function f is given by
                         straight f left parenthesis straight x right parenthesis space equals space fraction numerator 4 space sin space straight x space minus space 2 straight x minus space straight x space cosx over denominator 2 plus cos space straight x end fraction
is (i) increasing    (ii)  decreasing

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163.

Determine the values of x for which the function straight f left parenthesis straight x right parenthesis space equals fraction numerator straight x over denominator straight x squared plus 1 end fraction is increasing and for which it is decreasing.

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 Multiple Choice QuestionsShort Answer Type

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164. Prove that the function x2 – x + 1 is neither increasing nor decreasing on (0, 1).


Let straight f left parenthesis straight x right parenthesis space equals space straight x squared minus straight x plus 1
      straight f apostrophe left parenthesis straight x right parenthesis space equals space 2 straight x minus 1
Now,    straight f apostrophe left parenthesis straight x right parenthesis space greater than space 0 space space space space for space space straight x greater than 1 half space space and space straight f apostrophe left parenthesis straight x right parenthesis space less than 0 space space for space straight x space less than space 1 half.
therefore space space space straight f left parenthesis straight x right parenthesis space is space increasing space in space open parentheses 1 half comma space 1 close parentheses space and space decreasing space in space open parentheses 0 comma space 1 half close parentheses
therefore space space space space straight f left parenthesis straight x right parenthesis space is space neither space increasing space nor space decreasing space in space left parenthesis 0 comma space 1 right parenthesis

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165.

Let I be any interval disjoint from (– 1, 1). Prove that the function f given by straight f apostrophe left parenthesis straight x right parenthesis space equals space straight x plus 1 over straight x is strictly increasing on I.

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166.

Find the intervals in which the following function is decreasing:
f (x) = x– 12x

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167.

Find the intervals in which the function f given by f(x) = 2x2 – 3x is
(a) strictly increasing    (b) strictly decreasing

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168.

Find the intervals in which the function f given by f(x) = x2 – 4x+6  is
(a) strictly increasing    (b) strictly decreasing

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169.

Find the intervals in which the following functions are strictly increasing or decreasing:
x2+ 2x – 5

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170.

Find the intervals in which the following functions are strictly increasing or decreasing:
10 – 6x – 2x2

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