A wire of length 20 cm is bent in the form of a sector of a circl

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 Multiple Choice QuestionsMultiple Choice Questions

681.

The tangent to a given curve y = f(x) is perpendicular to the x-axis, if

  • dydx - 1

  • dxdy = 0

  • dxdy = 1

  • dydx = 0


682.

The minimum value of 27cos2x 81sin2x is

  • - 5

  • 15

  • 1243

  • 127


683.

A stone is thrown vertically upwards from the top of a tower 64 m high according to the law s = 48t - 16t2. The greatest height attained by the stone above ground is

  • 36 m

  • 32 m

  • 100  m

  • 64 m


684.

The length of the subtangent at t on the curve x = at + sint, y = a1 - cost

  • asint

  • 2asint2tant2

  • 2asint2

  • 2asin3t2sect2


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685.

A wire of length 20 cm is bent in the form of a sector of a circle. The maximum area that can be enclosed by the wire is

  • 20 sq cm

  • 25 sq cm

  • 10 sq cm

  • 30 sq cm


B.

25 sq cm

Given that,

length of the wire P = 20cm

Then, P = diameter + arc length

20 = 2r + S

 S = 20 - 2r

S = 2(10 - r)       ...(i)

Also, know that area of semicircle

A = 12πr2               ...iiA = 12πrr Angle = ArcRadius π = Sr S =  for straight length ofwire A = 12 s . r       ...iii

From Eq. (i),A = 12 . 210 - r . rA = 10r - r2                      ...ivNow, dAdr = 10 - 2rFor max or min area of enclosed by wire  dAdr = 0  10 - 2r = 0 r = 5Then, from Eq. (iv)A = 105 - 52A = 50 - 25    = 25 sq unit


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686.

The condition for the line y = mx + c to be a normal to the parabola y2 = 4ax is

  • c = - 2am - am3

  • c = - am

  • c = am

  • c = 2am + am3


687.

P is the point of contact of the tangent form the origin to the curve y = loge(x). The length of the perpendicular drawn form the origin to the normal at P is

  • 12e

  • 1e

  • 2e2 + 1

  • e2 +1


688.

For the curve 4x5 = 5y4, the ratio of the cube of the subtangent at a point on the curve the square of the subnormal at the same point is

  • 445

  • 544

  • 4454

  • 544


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689.

The set of real values of x for which f(x) = xlogx is increasing is

  • x :x  e

  • empty

  • {x : x < e}

  • {1}


690.

A sphere increases its volume at the rate of π cc/s. The rate at which its surface area increases when the radius is 1 cm is

  • 2π sq cm/s

  • π sq cm/s

  • 3π2 sq cm/s

  • π2 sq cm/s


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