Find the area of the circle 4x2 + 4y2 = 9 which is interior to

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 Multiple Choice QuestionsShort Answer Type

61.

Find the area of the region {(x, y): x2 + y2 ≤ 1 ≤ x + y}.

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 Multiple Choice QuestionsLong Answer Type

62.

Find the area of the region bounded by the circle x2 + y2 = 1 and x + y = 1. Also draw a rough sketch.

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63.

Find the area of the region {(x, y): x2 ≤ y ≤ |x|}.
Or
Find the area of the region bounded by the parabola y = x2 and y = |x|.

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64. Draw the rough sketch and find the area of the region:
{(x, y) : y2 ≤ 8 x, x2 + x2 ≤ 9} 
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65. Find the area of the region {(x, y): y2 ≤ 4 x, 4x2 + 4 y2 ≤ 9}
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66. Find the area lying above x-axis and included between the circle x2 + y2 = 8 x and inside of the parabola y2 = 4 x.
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67. Calculate the area enclosed in the region:
open curly brackets left parenthesis straight x comma space straight y right parenthesis space semicolon space space straight x squared plus straight y squared space less or equal than space 1 space less than space straight x plus 1 half straight y close curly brackets
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68. Find the area of the circle x2 + y2 = 16 which is exterior to the parabola y2 = 6x. 

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69. Find the area of the circle 4x2 + 4y2 = 9 which is interior to the parabola y2= 4 x. 


Consider the equations
           straight y squared space equals space 4 straight x                                   ...(1)
and    4 straight x squared plus 4 straight y squared equals 9
i.e.,    straight x squared plus straight y squared space equals space 9 over 4                           ...(2)
From (1) and (2), we get,
              straight x squared plus 4 straight x equals 9 over 4 space or space space 4 straight x squared plus 16 straight x minus 9 space equals space 0

therefore space space space straight x space equals space fraction numerator negative 16 plus-or-minus square root of 256 plus 144 end root over denominator 8 end fraction equals fraction numerator negative 16 plus-or-minus 20 over denominator 8 end fraction equals space 1 half comma space minus 9 over 2

therefore space space space space from space left parenthesis 1 right parenthesis comma space space space straight y squared space equals space 1 half                     open square brackets because space space straight y squared equals negative 9 over 2 space does space not space give space real space points close square brackets

therefore space space space space straight y space equals space fraction numerator 1 over denominator square root of 2 end fraction comma space minus fraction numerator 1 over denominator square root of 2 end fraction

therefore space space space space curve space left parenthesis 1 right parenthesis space and space left parenthesis 2 right parenthesis space intersect space in space the space points
                   straight P open parentheses 1 half comma space fraction numerator 1 over denominator square root of 2 end fraction close parentheses space and space straight Q space equals space open parentheses 1 half comma space minus fraction numerator 1 over denominator square root of 2 end fraction close parentheses

From P, draw PM space perpendicular space straight x minus axis
Here OA space equals space 3 over 2
Required area = Area of shaded region
= 2 (area of region OAPO) = 2 [area of region OMPO + area of region MAPM]

equals space 2 open square brackets integral subscript 0 superscript 1 divided by 2 end superscript 2 square root of straight x dx plus integral subscript 1 divided by 2 end subscript superscript 3 divided by 2 end superscript square root of 9 over 4 minus straight x squared end root close square brackets space equals space 4 integral subscript 0 superscript 1 divided by 2 end superscript straight x to the power of 1 divided by 2 end exponent dx plus 2 integral subscript 1 divided by 2 end subscript superscript 3 divided by 2 end superscript square root of open parentheses 3 over 2 close parentheses squared minus straight x squared end root dx
equals space 4 open square brackets fraction numerator straight x to the power of begin display style 3 over 2 end style end exponent over denominator begin display style 3 over 2 end style end fraction close square brackets subscript 0 superscript 1 half end superscript plus 2 open square brackets fraction numerator straight x square root of begin display style 9 over 4 minus straight x squared end style end root over denominator 2 end fraction plus open parentheses begin display style 3 over 2 end style close parentheses squared over 2 sin to the power of negative 1 end exponent open parentheses fraction numerator straight x over denominator 3 divided by 2 end fraction close parentheses close square brackets subscript 1 half end subscript superscript 3 over 2 end superscript
equals space 8 open square brackets straight x to the power of 3 divided by 2 end exponent close square brackets subscript 0 superscript 1 divided by 2 end superscript space plus space 2 space open square brackets 1 half straight x square root of 9 over 4 minus straight x squared end root plus 9 over 8 sin to the power of negative 1 end exponent open parentheses fraction numerator 2 straight x over denominator 3 end fraction close parentheses close square brackets subscript 1 half end subscript superscript 3 over 2 end superscript
equals space 8 over 3 open square brackets open parentheses 1 half close parentheses to the power of 3 over 2 end exponent minus 0 close square brackets plus space 2 open square brackets open parentheses 0 plus 9 over 8 sin to the power of negative 1 end exponent 1 close parentheses minus open curly brackets 1 fourth square root of 9 over 4 minus 1 fourth end root plus 9 over 8 sin to the power of negative 1 end exponent 1 third close curly brackets close square brackets
equals space 8 over 3 fraction numerator 1 over denominator 2 square root of 2 end fraction plus 2 open square brackets 9 over 8 cross times straight pi over 2 minus fraction numerator 1 over denominator 2 square root of 2 end fraction minus 9 over 8 sin to the power of negative 1 end exponent open parentheses 1 third close parentheses close square brackets
equals space fraction numerator 4 over denominator 3 square root of 2 end fraction plus fraction numerator 9 straight pi over denominator 8 end fraction minus fraction numerator 1 over denominator square root of 2 end fraction minus 9 over 4 sin to the power of negative 1 end exponent open parentheses 1 third close parentheses
equals space open parentheses fraction numerator 4 square root of 2 over denominator 6 end fraction minus fraction numerator square root of 2 over denominator 2 end fraction close parentheses plus fraction numerator 9 straight pi over denominator 8 end fraction minus 9 over 4 sin to the power of negative 1 end exponent open parentheses 1 third close parentheses space equals space fraction numerator square root of 2 over denominator 6 end fraction plus fraction numerator 9 straight pi over denominator 8 end fraction minus 9 over 4 sin to the power of negative 1 end exponent open parentheses 1 third close parentheses

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70. Draw a rough sketch of the region {(x, y): y2 ≤ 5 x, 5 x2 + 5 y2 ≤ 36} and find the area enclosed by the region using method of integration.
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