If the adjoining figure is a sector of a circle of radius 10.5 c
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    45.

    In Fig. 12.44, the shape of the top of a table in a restaurant is that of a sector of a circle with centre O and ∠BOD = 90°. If BO = OD = 60 cm, find
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    Fig. 12.44.

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    46. If the adjoining figure is a sector of a circle of radius 10.5 cm, find the perimeter of the sector.   open parentheses bold Taken bold space bold pi bold space bold equals bold space bold 22 over bold 7 close parentheses.

    Here, r = 10.5 cm and ө = 60°

    Here, r = 10.5 cm and ө = 60°Now,Length of Arc Now,  Perimeter of
    Now,
    Length of Arc left parenthesis straight A with overbrace on top space straight B with overbrace on top right parenthesis space equals space 2 space πr space straight x space straight theta over 360 equals space 2 cross times 22 over 7 straight x space 10.5 space straight x space 60 over 360 equals space 11 space cm.
    Now,  Perimeter of sector 
                = 2r + length of Arc open parentheses straight A with overbrace on top space straight B with overbrace on top close parentheses
                = 2 x 10.5 + 11 
                = 21 + 11 = 32 cm
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