In a circle of radius 21 cm, an arc subtends an angle 60° at the centre. Find
(i) the length of the arc
(ii) area of the sector formed by the arc.
(iii) area of the segment formed by the corresponding chord.
Here, we have
r = 21 cm
and ө = 60°
Area of circle =
Area of sector OACBO
And, Area of triangle (AOB)
Now,
(i) The length of the arc
(ii) Area of sector (OACBO) = 231 cm2
(iii) Area of minor segment (ACBA)
= Area of circle - Area of (∆AOB)
= (1386 - 190.95) cm2
= 1195.05 cm2
Two circles touch externally. The sum of their areas is 130π sq. cm and the distance between their centres is 14 cm. Find the radii of the circle.