In the given figure, ABED is a parallelogram in which DE = EC. Show that area (ABF) = area (BEC)
Given: ABCD is a parallelogram in which DE = EC To Prove: area (ABF) = area (BEC)
Proof: Â Â Â AB = DE
| Opposite sides of a parallelogram DE = EC Â Â Â | Given
∴ AB = EC Also, AB || DE
| Opposite sides of a parallelogram ⇒ AB || DC
Now, ΔABF and ΔBEC are on equal bases AB and EC and between the same parallels AB and DC
∴ ar(ΔABF) = ar(ΔBEC)
In the following figure, ABCD is a parallelogram and EFCD is a rectangle. Also, AL ⊥ DC. Prove that
(i) ar(ABCD) = ar(EFCD)
(ii) ar(ABCD) = DC x AL.