In the given figure, ABED is a parallelogram in which DE = EC. Show that area (ABF) = area (BEC)
From (1) and (2), we get
ar(AABC) = ar(ΔA'BC)
Hence, ΔABC and ΔA'BC are equal in area.
In the following figure, ABCD is a parallelogram and EFCD is a rectangle. Also, AL ⊥ DC. Prove that
(i) ar(ABCD) = ar(EFCD)
(ii) ar(ABCD) = DC x AL.