For what value of n, are the nth terms of two APs: 63, 65, 67, . . . and 3, 10, 17, . . . equal?
Find the sum of the following APs:
–37, –33, –29, . . ., to 12 terms.
Here, a = –31
d = –33 – (–37)
= – 33 + 37 = 4
n = 12
We know that,
= 6 [-74 + 11 x 4]
= 6 x [-74 + 44]
= 6 x (-30) = -180
Hence, the sum of First 12 terms of the given
A.P. = –180