Which term of the A .P. 3, 15, 27, 39 ... will be 120 more than

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 Multiple Choice QuestionsShort Answer Type

281.  Write the common difference of an A .P. whose nth term is 3n + 5. 
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282. For what value of k, are the numbers x, 2x + k and 3x + 6 three consecutive terms of an A .P
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283. The 17th term of an A .P. exceeds its 10th term by 7. Find the common difference.
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284. If 9th term of an A .P. is zero. Prove that 29th term is double of its 19th term. 
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285. If 5th term of an A .P. is zero. Prove that its 23rd term is three times its 11th term.
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286. How many numbers of two digits are divisible by 7?
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287. Which term of the A .P. 3, 15, 27, 39 ... will be 120 more than its 21st term?


Here,      a = 3,  d = 15 - 3 = 12

Here,      a = 3,  d = 15 - 3 = 12Hence, 31st term is 120 more t
Hence, 31st term is 120 more than its 21st term.
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288. Which term of the A .P. 4, 12, 20, 28, ... will be 120 more than its 21st term?
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289. Determine the A .P. whose 3rd term is 5 and the 7th term is 9.
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290. How many two digit numbers which are multiples of 5 lie between 10 and 100 ?
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